Explicación paso a paso:
Usando metodo de sustitucion
[tex]5x + 2x = 1 \\ - 3x + 3y = 5[/tex]
[tex]5x + 2x = 1 = x = \frac{1}{7} [/tex]
Sustituir
[tex]3 \times \frac{1}{7} + 3y = 5[/tex]
Simplificar
[tex] \frac{3}{7} + 3y = 5 \\ y = \frac{32}{21} [/tex]
Respuesta
[tex]x = \frac{1}{7} \\ y = \frac{32}{21} [/tex]
Espero te sirva :)
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Explicación paso a paso:
Usando metodo de sustitucion
[tex]5x + 2x = 1 \\ - 3x + 3y = 5[/tex]
[tex]5x + 2x = 1 = x = \frac{1}{7} [/tex]
Sustituir
[tex]3 \times \frac{1}{7} + 3y = 5[/tex]
Simplificar
[tex] \frac{3}{7} + 3y = 5 \\ y = \frac{32}{21} [/tex]
Respuesta
[tex]x = \frac{1}{7} \\ y = \frac{32}{21} [/tex]
Espero te sirva :)