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y = 4x + 1
y = y
x² + 2x + k = 4x + 1
x² + 2x - 4x + k - 1 = 0
x² - 2x + k - 1 = 0
syarat sistem mempunyai dua penyelesaian
D > 0
b² - 4ac > 0
(-2)² - 4.1.(k - 1) > 0
4 - 4k + 4 > 0
8 - 4k > 0
2 - k > 0
-k > -2
k < 2