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⇔ sin²x + 2sinx.cosx + cos²x + sin²x - 2sinx.cosx + cos²x
⇔ 2(sin²x + cos²x)
⇔ 2(1)
⇔ 2
= (sin^2 x + 2 sin x cos x + cos^2 x) + (sin^2x -2sin x cos x + cos ^2 x)
= sin ^2x + sin ^2x + cos ^2x +cos ^2x
= sin^2x + cos^2x + sin^2 x+ cos^2x
= 1+ 1
= 2