Sin 330° tan (-210)° - cos (210)° cotan (315)°
ini soal trigonometri kelas 10. makasih ya untuk bantuannya
ini soal trigonometri kelas 10. makasih ya untuk bantuannya
ekamiaww
![[sin 330. tan (-210)] - [cos (210).cotan (315)] \\ =[- \frac{1}{2}.- \frac{1}{3} \sqrt{3} ]-[-\frac{1}{2} \sqrt{3}.-1] \\ = \frac{1}{6} \sqrt{3} -\frac{1}{2} \sqrt{3} \\ =\frac{1}{6} \sqrt{3} -\frac{3}{6} \sqrt{3} \\ =- \frac{2}{6} \sqrt{3} \\ =- \frac{1}{3} \sqrt{3}](https://tex.z-dn.net/?f=%5Bsin+330.+tan+%28-210%29%5D+-+%5Bcos+%28210%29.cotan+%28315%29%5D+%5C%5C+%3D%5B-+%5Cfrac%7B1%7D%7B2%7D.-+%5Cfrac%7B1%7D%7B3%7D+%5Csqrt%7B3%7D+%5D-%5B-%5Cfrac%7B1%7D%7B2%7D+%5Csqrt%7B3%7D.-1%5D+%5C%5C+%3D+%5Cfrac%7B1%7D%7B6%7D+%5Csqrt%7B3%7D++-%5Cfrac%7B1%7D%7B2%7D+%5Csqrt%7B3%7D+%5C%5C+%3D%5Cfrac%7B1%7D%7B6%7D+%5Csqrt%7B3%7D++-%5Cfrac%7B3%7D%7B6%7D+%5Csqrt%7B3%7D+%5C%5C+%3D-+%5Cfrac%7B2%7D%7B6%7D++%5Csqrt%7B3%7D++%5C%5C+%3D-+%5Cfrac%7B1%7D%7B3%7D++%5Csqrt%7B3%7D+ "[sin 330. tan (-210)] - [cos (210).cotan (315)] \\ =[- \frac{1}{2}.- \frac{1}{3} \sqrt{3} ]-[-\frac{1}{2} \sqrt{3}.-1] \\ = \frac{1}{6} \sqrt{3} -\frac{1}{2} \sqrt{3} \\ =\frac{1}{6} \sqrt{3} -\frac{3}{6} \sqrt{3} \\ =- \frac{2}{6} \sqrt{3} \\ =- \frac{1}{3} \sqrt{3}")
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