Question

simplificar los siguientes radicales




heeeelp​

Answer 1

Verified answer

[tex]1) \sqrt{588} = \sqrt{ {2}^{2} \times 3 \times {7}^{2} } = 2 \times 7 \times \sqrt{3} = 14 \sqrt{3} [/tex]

[tex]2) \sqrt[3]{135} = \sqrt[3]{5 \times {3}^{3} } = 3 \sqrt[3]{5} [/tex]

[tex]3) \sqrt[3]{432} = \sqrt[3]{ {2}^{4} \times {3}^{3} } = 2 \times 3 \times \sqrt[3]{2} = 6 \sqrt[3]{2} [/tex]

[tex]4) \sqrt{32} = \sqrt{ {2}^{5} } = {2}^{2} \times \sqrt{2} = 4 \sqrt{2} [/tex]

[tex]5) \sqrt[3]{54} = \sqrt[3]{2 \times {3}^{3} } = 3 \sqrt[3]{2} [/tex]

[tex]6) \sqrt{60} = \sqrt{ {2}^{2} \times 3 \times 5} = 2 \times \sqrt{3 \times 5} = 2 \sqrt{15} [/tex]

[tex]7) \sqrt{ {x}^{6} } = {x}^{3} [/tex]

[tex]8) \sqrt{28} = \sqrt{ {2}^{2} \times 7} = 2 \sqrt{7} [/tex]

[tex]9) \sqrt[ 3]{24} = \sqrt[3]{ {2}^{3} \times 3 } = 2 \sqrt[3]{3} [/tex]

[tex]10) \sqrt{48} = \sqrt{ {2}^{4} \times 3 } = {2}^{2} \times \sqrt{3} = 4 \sqrt{3} [/tex]

[tex]11) \sqrt{ {x}^{9} } = {x}^{7} [/tex]