Question

Simpangan gelombang pada soal nomor 37 setelah bergetar 0,5 s adalah…

Answer 1

Verified answer

Jawaban:

y1 = 5 cm

y2 = 0 cm

Penjelasan:

Setelah bergetar t = 0,5 s

y1 = 10.sin π(5 t+ 1/3 )

y1 = 10.sin π(5 . 0,5 + 1/3 )

y1 = 10.sin π(2,5 + 1/3)

y1 = 10. sin 2,83π

y1 = 10. sin 510°

y1 = 5 cm

y2 = 10.sin 2π (5 t)

y2 = 10.sin 2π (5 . 0,5)

y2 = 10. sin 5π

y2 = 10. sin 900°

y2 = 0