Question

Simpangan baku dari data 4, 5, 7, 3, 6 adalah ....

Answer 1

X=εX/n
 =(4+5+7+3+6)/5
 =5
s=√ε(X-x)²/n
  =√(4-5)²+(5-5)²+(7-5)²+(3-5)²+(6-5)²/5
  =√(1+0+4+4+1)/5
  =√10/5
  =√2