Jawaban:
2a. x= 5.
b. y= 15
4.a. x = 30
b. <DCE = 120°
<BCE = 25°
Penjelasan dengan langkah-langkah:
2.
[tex] \frac{ps}{st} = \frac{pr}{qr} \\ \frac{4}{x} = \frac{16}{20} \\ x = \frac{80}{16} = 5[/tex]
[tex] \frac{pt}{x} = \frac{pq}{qr} \\ \frac{3}{5} = \frac{3 + y}{20} \\ 15 + 5y = 60 \\ y = 15[/tex]
4.
[tex] <acd + < dce + < bce = 180 \\ (x + 15) + (3x + 20) + (x - 5) = 180 \\ 5x + 30= 180 \\ 5x = 150 \\ x = 30[/tex]
<DCE = 3x + 20
= 3(30) + 30
= 120
<BCE = x - 5
= 30 - 5 = 25
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Jawaban:
2a. x= 5.
b. y= 15
4.a. x = 30
b. <DCE = 120°
<BCE = 25°
Penjelasan dengan langkah-langkah:
2.
[tex] \frac{ps}{st} = \frac{pr}{qr} \\ \frac{4}{x} = \frac{16}{20} \\ x = \frac{80}{16} = 5[/tex]
[tex] \frac{pt}{x} = \frac{pq}{qr} \\ \frac{3}{5} = \frac{3 + y}{20} \\ 15 + 5y = 60 \\ y = 15[/tex]
4.
[tex] <acd + < dce + < bce = 180 \\ (x + 15) + (3x + 20) + (x - 5) = 180 \\ 5x + 30= 180 \\ 5x = 150 \\ x = 30[/tex]
<DCE = 3x + 20
= 3(30) + 30
= 120
<BCE = x - 5
= 30 - 5 = 25