Question

Siapa pun bantu jawab dong...

Answer 1

Verified answer

∫ 6x^2 (3x^3 - 1)^(-3/4) dx

Misal : u = 3x^3 - 1
=> du = 9x^2 dx
=> dx = du/(9x^2)

∫ 6x^2 (3x^3 - 1)^(-3/4) dx
= ∫ 6x^2 . u^(-3/4) du/(9x^2)
= ∫ 2/3 u^(-3/4) du
= (2/3)/(1/4) . u^(1/4) + C
= 8/3 ^4√u + C
= 8/3 ^4√(3x^3 - 1) + C

Answer 2

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