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=>a + b +c = 220 .........(I)
=>c = a/3 .......................(II)
=>a = 2b
a/2 = b .....................(III)
reemplazando (III) y (II) en (I)
a + a/2 + a/3 = 220
6a + 3a + 2a = 220*6
11a = 220*6
a = 20*6
a = 120
hallando en (III)
c = a/3 = 120/3 = 40
hallando en (II)
b = a/2 = 120/2 = 60
los angulos son 120, 60 ,40