Respuesta:
[tex]tan (x)+ctg( x)=4 \\ \frac{sen(x)}{cos(x)} + \frac{cos(x)}{sen(x)} = 4 \\ \frac{sen {}^{2} (x) + cos {}^{2} (x)}{sen (x) cos (x)} = 4[/tex]
[tex] \frac{1}{sen (x) cos (x)} = 4 \\ M = sen (x) cos (x) = \frac{1}{4} [/tex]
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
Respuesta:
[tex]tan (x)+ctg( x)=4 \\ \frac{sen(x)}{cos(x)} + \frac{cos(x)}{sen(x)} = 4 \\ \frac{sen {}^{2} (x) + cos {}^{2} (x)}{sen (x) cos (x)} = 4[/tex]
[tex] \frac{1}{sen (x) cos (x)} = 4 \\ M = sen (x) cos (x) = \frac{1}{4} [/tex]