Respuesta:
Explicación paso a paso:
Secα . Cscα = 5
Calcular R = Tg²α + Ctg²α
R = Tg²α + Ctg²α
R = Sec²α - 1 + Cos²α - 1
R = Sec²α + Cos²α - 2
R = (1/Cosα)² + (1/Senα)² - 2
R = 1/(Sen²α)(Cos²α) - 2
(Secα . Cscα)² = 5²
Sec²α . Csc²α = 25
R = 1/25 - 2
R = -49/25
III cuadrante
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Verified answer
Respuesta:
Explicación paso a paso:
Secα . Cscα = 5
Calcular R = Tg²α + Ctg²α
R = Tg²α + Ctg²α
R = Sec²α - 1 + Cos²α - 1
R = Sec²α + Cos²α - 2
R = (1/Cosα)² + (1/Senα)² - 2
R = 1/(Sen²α)(Cos²α) - 2
(Secα . Cscα)² = 5²
Sec²α . Csc²α = 25
R = 1/(Sen²α)(Cos²α) - 2
R = 1/25 - 2
R = -49/25
Respuesta:
III cuadrante
Explicación paso a paso: