Si pΔq = p²-q² , halla (5Δ2) - (4Δ1)
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Respuesta:
Hola!
Explicación paso a paso:
P Δ Q = P² - Q²
Halla ( 5 Δ 2 ) - ( 4 Δ 1 )
Reemplazamos:
( 5 Δ 2 ) : P² - Q²
5² - 2² :
25 - 4 : 21
( 4 Δ 1 ) : P² - Q²
4² - 1² :
16 - 1 : 15
Entonces
( 5 Δ 2 ) - ( 4 Δ 1 ) :
21 - 15 = 6
La respuesta final es 6
Espero ayudarte :)