SI P (x) = x2+5x +1 HALLAR :P (1) + P(-1).... Question from @95650350

December 2023 1 2 Report

SI P (x) = x2+5x +1 HALLAR :P (1) + P(-1)

luana10sc

Respuesta:

P(x+5)=x²+5x-1

Entonces igualamos para saber el valor de x

x + 5= 4

x = -1

Entonces

P(-1) = -1² + 5(-1) - 1

P(-1) = 1 - 5 - 1

P(-1) = -4 - 1

P(-1) = -5

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