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L*A = 168 ec. 2
Sustituyendo valores de la ec. 1 en la ec. 2:
(17+A)*A = 168
A²+17A = 168
A²+17A-168 = 0
A ={-17+-(√17²-4*1*-168)} / 2*1
A = {-17 +-(√289+672)} / 2
A = {-17 +-√961} / 2
A = {-17 +- 31} / 2
A₁ = {-17-31}/2 = -48/2 = -24
A₂ = {-17+31}/2 = 14/2 = 7
De la ec. 1:
L = 17+A
L = 17+7
L = 24
Area = 7*24 = 168
Las dimensiones del rectángulo son:
ancho: 7 cms
Largo: 17 cms
Saludos.....