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primero f(3)
f(3)=2*(3)-1 (es solo remplazar el valor en este caso 3 en x)
f(3)=6-1=5
segundo f(2)
f(2)=2*(2)-1
f(2)=4-1
f(2)=3
remplazamos f(3) y f(2)
f(3) - f(2)
5 - 3 = 2
Rta = 2
f(3)=2(3)-1=5
f(2)=2(2)-1=3
entonces f(3)-f(2)=5-3=2