Si en un triangulo, el angulo B es 5° menor que el angulo A y el angulo C es el doble del angulo B, ¿Cuanto mide cada angulo?
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A + B + C = 180°
C = 2B
B = A - 5
A = B+5
B+5+B+2B = 180
5B = 175
B = 35°
C = 2(35)
C = 70°
A = 35+5
A = 40°
Por tanto
A = 40°
B = 35°
C = 70°