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empecemos con: 10 @ 5
10 @ 5 = 5² - 2√(10 x 5 -1) + 2 resolvamos
= 25 - 2√(50- 1) + 2
= 25 - 2√49 + 2
= 25 - 2 (7) + 2
= 25 - 14 + 2
= 25 -12
= 13
nos queda : 13 @ 5 ÷ 11
resolvemos ahora: 13 @ 5 = 5² - 2√(13 x 5 - 1) +2
= 25 - 2√(65 - 1) +2
= 25 - 2√64 + 2
= 25 - 2(8) + 2
= 25 - 16 + 2
= 25 - 1
= 11
nos queda: 11 ÷ 11 que nos dará 1
Rta. : opción d
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