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eliminamos los %
5(10) (4) m = 12 (20) (5) n
10(4) m = 12(20)n
4m = 12(2)n
m = 6n
(2n + 3m) ?% = (2m-3n)
(2n + 3(6n)) ?% = 2(6n) - 3n
20n x ?% = 9n
20 x ? % = 9
? % = 9/20
? = (9/20) (100)
? = 45
R/ 45%