si cos(2x²+4x-20) x sec(x²+4x+44)=1 determina el valor de "x".... Question from @nevenkapolack

August 2023 1 6 Report

si cos(2x²+4x-20) x sec(x²+4x+44)=1 determina el valor de "x"

Explicación paso a paso:

SEC(Ø).COS(Ø) = 1

2x² + 4x - 20 = x² + 4x + 44

x² - 64 = 0

x² = 64

lxl = 8

x = -8 ó 8

si no te dan clave consideralo X = 8 (ya no pongas lxl)

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