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3X = Triple de la edad
2X = Doble de la edad
Condicion
3X - 19 = 2X + 9
3X - 2X = 19 + 9
X = 28
Prueba
3(28) - 19 = 84 - 19 = 65
2(28) + 9 = 56 + 9 = 65
El profesor tiene 28 años