a#b=(a-b)(a+b) a#b=(a-b)(a+b)
5#2=(5-2)(5+2) a#b=(7-4)(7+4)
5#2=(3)(7) a#b=(3)(11)
5#2=21 a#b=33
∵K=4#2
COMPROBAMOS:
4#2=(4-2)(4+2)
4#2=(2)(6)
4#2=12
∵12+21=33
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a#b=(a-b)(a+b) a#b=(a-b)(a+b)
5#2=(5-2)(5+2) a#b=(7-4)(7+4)
5#2=(3)(7) a#b=(3)(11)
5#2=21 a#b=33
∵K=4#2
COMPROBAMOS:
4#2=(4-2)(4+2)
4#2=(2)(6)
4#2=12
∵12+21=33