Si:
A c B c C
n(B)= n(A)+5
n(C)=2 X n(B)
n(A)+ n(B) + n(C)= 27
halla
n[P(C-B)]
A c B c C
n(B)= n(A)+5
n(C)=2 X n(B)
n(A)+ n(B) + n(C)= 27
halla
n[P(C-B)]
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A= x
B= X + 5
C= 10 + 2X
x +x +5 +10 +2x = 27
x= 3
10 + 2x- x- 5= 5 +x = 8
2 elevado a la 8 = 256
rpta= 256 listo :3
dime si hay respuesta porfa u.u