" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
1)...x#3=2(x)+3
......x#3=2x+3
2)...1#2=2(1)+2
......1#2=4
Ahora remplazamos..
(2x+3#4)= 2(2x+3)+4
(2x+3#4)= 4x+6+4
(2x+3#4)= 4x+10
Ahora remplazamos
4x+10=14
4x=14-10
4x=4
x=1
Entonces "x" vale 1...salu2
(X ≠ 3) ≠ (1 ≠ 2) = 14
(M) ≠ (2×1 + 2) = 14
(M) ≠ (4) = 14
2×M + 4 = 14
2M = 10
M= 5
Pero M = (X ≠3)
(X≠3) = 5
2X + 3 = 5
2X = 2
X = 1
∴ ENTONCES X = 1
SUERTE XD