Question

Si: 2tgx + secx =2
Hallar E=cosx - senx

Answer 1

L
        .
      /xl
  b/    l a
 /____l
   c
2tgx+secx=2
2c/a + b/a =2
(2c+b)/a=2
2c+b=2a
b=2(a-c)

E= cosx-senx
E= a/b-c/b
E=(a-c)/b
E=(a-c)/2(a-c)
E=1/2