show that 4a2c2-(a2-b2+c2)2=16s(s-a)(s-b)(s-c).... Question from @cwlioe4

cwlioe4 @cwlioe4

November 2022 0 3 Report

show that 4a2c2-(a2-b2+c2)2=16s(s-a)(s-b)(s-c)

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