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Verified answer
Kelas 8 MatematikaBab Barisan dan Deret Bilangan
r = ⁶⁻¹√(U6 / U1)
r = ⁵√(486 / 2)
r = ⁵√243
r = 3
Sn = a . (rⁿ - 1) / (r - 1)
S6 = 2 . (3⁶ - 1) / (3 - 1)
S6 = 2 . (729 - 1) / 2
S6 = 728 m
s6 = 728
s = 728/6
= 121,3