Panjang dawai 50 cm
Dik
m = 5 gr = 0,005 kg
T = 100 N
Nada dasar = n = 1
f1 = 100 Hz
n = 1
Dit L?
μ = m/L
fn = (n/2L) √(F/μ)
f1 = (1/2L) √(100/(m/L))
100 = (1/2L) √(100L/m)
100 x 2L = √(100L/0,005)
(200L)² = 20.000L
40.000L² = 20.000L
dibagi 20.000
2L² = L
2L² - L = 0
L (2L - 1) = 0
L = 0 tdk mgkn
atau
2L-1 = 0
2L = 1
L = 1/2 m = 50 cm
Kategorisasi
Kelas : XI
Mapel : Fisika
Materi : Gelombang bunyi
Kode Kategorisasi : 11.6.9.
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Panjang dawai 50 cm
Dik
m = 5 gr = 0,005 kg
T = 100 N
Nada dasar = n = 1
f1 = 100 Hz
n = 1
Dit L?
μ = m/L
fn = (n/2L) √(F/μ)
f1 = (1/2L) √(100/(m/L))
100 = (1/2L) √(100L/m)
100 x 2L = √(100L/0,005)
(200L)² = 20.000L
40.000L² = 20.000L
dibagi 20.000
2L² = L
2L² - L = 0
L (2L - 1) = 0
L = 0 tdk mgkn
atau
2L-1 = 0
2L = 1
L = 1/2 m = 50 cm
Kategorisasi
Kelas : XI
Mapel : Fisika
Materi : Gelombang bunyi
Kode Kategorisasi : 11.6.9.