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• kacamata
PP = 50 cm
PR = 2 m
P = __?
koreksi jarak jauh
P = - 1 / PR
P = - ½ D
koreksi jarak dekat
P = 4 - 100 / PP
P = 4 - 100 / 50
P = 2 D
orang tsb harus menggunakan kacamata bifokal dengan kekuatan lensa -½ D dan +2 D