October 2018 1 31 Report
Seratus ml larutan asam lemah HA 0,1m(pH=5) dicampur dengan 100 ml larutan NH3 0,1 M (pH=11).berapakah pH dari larutan hasil pencampuran?
(kb NH3 = 10^-5)
tolong dijawab ya,kasih caranya jga
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