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jawab:
CuSO₄.xH₂O = artinya
CuSO₄ = 64%
xH₂O = 36%
sehingga massa totalnya = 100%
mr CuSO₄ = 64 + 32 + 64 = 160 ----> mol = 64/160 = 0,4 mol
mr H₂O = 2 + 16 = 18 ---> mol = 36/18 = 2 mol
per bandingannya
1 : x = 0,4: 2
1/x = 0,4/2
0,4 x = 2
x = 2/0,4 = 5
sehingga rumusnya : CuSO₄.5H₂O