Selesaikanlah! a. 2 sin 150 derajat + 3 cos 240 derajat b. 4 cos kuadrat 300 derajat + 4 sin kuadrat 300 derajat #tolong bantu ya sama carnya
Ridwan3107
A. →2sin150° = sin (180°-30°) kw 2 = sin 30° = 1/2×2 =1 →3cos240°=cos (180°+30°) kw 3 = cos 30° = (-1/2 akar 3) × 3 =-3/2 akar 3. ▲ 1+(-3/2 akar 3) =-3 akar 3
→2sin150° = sin (180°-30°)
kw 2 = sin 30°
= 1/2×2 =1
→3cos240°=cos (180°+30°)
kw 3 = cos 30°
= (-1/2 akar 3) × 3
=-3/2 akar 3.
▲ 1+(-3/2 akar 3)
=-3 akar 3