Question

Selesaikan sistem persamaan linear dua variabel berikut dengan METODE SUBTITUSI
3x+4y=18
5x-2y=4

Answer 1

3x+4y=18 x 5 = 15x+20y=90
5x-2y=4 x 3 = 15x-2y= 12
 di kurangi
22y=78
y=3,5455

3x+4y = 18
3x+4.3,5455=18
3x+14,18=18
3x=18-14,18
x=1,273

Answer 2

3x + 4y = 18 -> y=18-3x/4 persmaan (1)
5x-2y=4 persmaan (2)
subsitusi kn per (1) & (2)
5x - 2 (18/4-3x/4)=4
5x- (36/4+6x/4)=4
20x/4 - 36/4+ 6x /4 = 4
26x/4 = 4 + 36/4
26x/4= 16/4 + 36/4
26x/4= 52/4
26x * 4= 52*4
104x=208
x=2

msukn nilai x;
y= 18/4 - 3x/4
= 18/4 - 3 (2)/4
= 18/4 - 6/
= 24/4= 6

jdi.
Hp = {2,6}