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2x-y-5 = x+y => 2x -x -y -y -5 = 0
=> x-2y-5= 0 ...(i)
x-y+12 = x+ 2y => x-x-y-2y+12 = 0
=> -3y+ 12 = 0
=> -3y = -12
=> y = -12/-3 = 4
subtitusikan ke persamaan pertama
x-2y-5 = 0
x-2(4) -5 = 0
x -8-5=0
x=8+5=13. nilai x=13 dan y=4