Question

Selesaikan persamaan kuadrat berikut:
1. 4x-12x+9=0
2. 4x²+20x+25=0
3. 2x²+5x-12=0
4. 2x²+5x-7=0
5. 6x²-13x+6=0
Bantu ya :mewek:

Answer 1

1. 4x-12x+9 = 0                          1. 4x²-12x+9 = 0
    -8x = -9                                      (2x-3) (2x-3) = 0
     x = 9/8 -> x = 1 1/8                    2x-3 = 0
2. 4x²+20x+25 = 0                           2x = 3
    (2x+5) (2x+5) = 0                          x = 3/2 - > x = 1 1/2
    2x+5 = 0
    2x = -5
    x = -5/2 -> x = -2 1/2
3. 2x²+5x-12 = 0
    (2x-3) (x+4) = 0
    2x-3 = 0
    2x = 3
    x = 3\2 -> x = 1 1/2
    x+4 = 0
    x = -4
4. 2x²+5x-7 = 0
    (2x+7) (x-1) = 0
    2x+7 = 0
    2x = -7
    x = -7/2 -> x = -3 1/2
    x-1 = 0
    x = 1
5. 6x²-13x+6 = 0
    (3x-2) (2x-3) = 0
    3x-2 = 0
    3x = 2
    x = 2/3
    2x-3 = 0
    2x = 3
    x = 3/2 -> 1 1/2