Question

Selesaikan Persamaan Berikut Dengan Menggunakan Rumus ABC!!

1. ( t - 1 ) x² + 2tx + t + 1 = 0

Ane Kasih Poin gede dahhh..

Answer 1

A= (t-1)
b = 2t
c= 1
..
x12 = - b ± √(b²-4ac) / { 2a)
x12 = - 2t± √(4t²-4(t-1)(1) / (2(t-1)) 
x12 = - 2t ±√ {4t²-4t+4) / (2(t-1))
x12 = - 2t ± 2√(t²-t+1) / 2(t-1)
x12 = 2 (-t ± √(t²-t+1) / 2 (t-1)
x12 = { -t ± √(t²-t+1) / (t-1)
x1 = (-t+ √(t²-t+1) / (t-1)
x2 = (-t- √(t²-t+1) / (t-1)