|x + 6| < 1
(x + 6)² < 1²
x² + 12x + 36 < 1
x² + 12x + 36 - 1 < 0
x² + 12x + 35 < 0
(x + 5)(x + 7) ≥ 0
Pembuat nol:
x + 5 = 0
x = -5
x + 7 = 0
x = -7
Tes x = 0
= x² + 12x + 35
= (0)² + 12(0) + 35
= 35 > 0
Jadi, himpunan penyelesaian |x + 6| < 1 adalah {-7 < x < -5}.
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|x + 6| < 1
(x + 6)² < 1²
x² + 12x + 36 < 1
x² + 12x + 36 - 1 < 0
x² + 12x + 35 < 0
(x + 5)(x + 7) ≥ 0
Pembuat nol:
x + 5 = 0
x = -5
x + 7 = 0
x = -7
Tes x = 0
= x² + 12x + 35
= (0)² + 12(0) + 35
= 35 > 0
Jadi, himpunan penyelesaian |x + 6| < 1 adalah {-7 < x < -5}.