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v = 10 m/s
g = 10 m/s²
h = ? [m]
Ep = mgh
Ek = 0,5mv²
Z zasady zachowania energii:
Ep = Ek
mgh = 0,5mv² /:mg
h = 0,5mv²/mg
h = v²/2g
[h] = [ (m/s)² :(m/s²) = (m²/s²)*(s²/m) = m]
h = 10²/2*10 m
h = 100/20 m
h = 5 m
Odp: Piłka wzniesie się na wysokość 5 m.