segitiga ABC siku-siku di C panjang BC 5 cm dan panjang AC 12 cm Tentukan panjang AB dan keliling segitiga ABC
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AB² = AC² + BC²
= 12² + 5²
= 144 + 25
AB = √169
= 13
K = AB + AC + BC atau a + b + c
= 13 + 12 + 5
= 25 + 5
= 30