¿que masa tendra un cuerpo que se encuentra a 530 m de altura para que el mismo tenga una EPG de 900.... Question from @mirtagenes

humocefalo La EPG es igual a la altura por el peso
EPG=h x P
y el peso es igual a la masa por la aceleración (en este caso 9.8 m/s²)
P= m x 9.8

Metemos la ecuación del peso en la de la EPG, sustituyendo.

EPG= h x m x 9.8

Ahora sustituimos con los datos que tenemos.

9000 = 530 x m x 9.8

Despejamos la incógnita, que es justamente lo que queremos obtener en este problema.
9000/(530x9.8) = m
Hacemos la operación y obtenemos la masa del cuerpo.

m = 1.73 Kg

2 votes Thanks 1

Freddybarrios Datos
Ep = 9000 J
H = 530 m
G = 9,8 m/s²
Masa = ?

$Masa = \dfrac{Ep}{G\cdot H} = \dfrac{9000J}{9,8m/s^2\cdot 530m} = \dfrac{9000kg\cdot m^2/s^2}{5194m^2/s^2} =\bf 1,73\ Kg$

Saludos desde Venezuela

1 votes Thanks 0

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