Sederhanakanlah bentuk berikut ini tampa menggunakan kalkulator 1. log 4 (x+2)-log 4 6 =1 2. log3(x2.... Question from @anasaswar16

September 2018 2 19 Report

Sederhanakanlah bentuk berikut ini tampa menggunakan kalkulator
1. log 4 (x+2)-log 4 6 =1
2. log3(x2-3x+1)=0

nilai x adalah

MathSolver74 ⁴log (x + 2) - ⁴log 6 = 1
⁴log 6(x + 2) = 1
6x + 12 = 4
6x = - 8
x = - 4/3

³log (x² - 3x + 1) = 0
x² - 3x + 1 = 2°
x² - 3x + 1 = 1
x² - 3x = 0
x(x - 3) = 0
x = 0 atau x = 3

0 votes Thanks 1

AdindaAS 1. log 4(x+2) - log 4.6 = 1
$log \frac{4(x+2)}{4.6} = 1 \\ log \frac{x+2}{6} = 1 \\ \frac{x+2}{6} = 0$
x + 2 = 0
x = -2
2. $log 3(x^{2} - 3x + 1) = 0 \\ 10^{0} = 3x^{2} - 9x + 3 \\ 1 = 3x^{2} - 9x + 3 \\ 3x^{2} - 9x + 2 = 0$
$x_{1} = \frac{-b + \sqrt{ b^{2} - 4.a.c} }{-2a} \\ = \frac{9 + \sqrt{ (-9)^{2} + 4.3.2 } }{-2.3} \\ = \frac{9 + \sqrt{81 + 24} }{-6} \\ = \frac{9 + \sqrt{105} }{-6}$
$x_{2} = \frac{-b - \sqrt{ b^{2}- 4.a.c } }{-2a} \\ = \frac{9 - \sqrt{ (-9)^{2} - 4.3.2 } }{-2.3} \\ = \frac{9 - \sqrt{81 - 24} }{-6} \\ = \frac{9 - \sqrt{57} }{-6}$

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