Question

sederhanakan bentuk pangkat berikut

tolong kakak2, makasih ​

Answer 1

SOAL A.

• [tex]{p}^{5} \times {(p \times q)}^{3} \times (\frac{1}{ {p}^{2} \times q})[/tex]
• [tex]= {p}^{5} \times ({p}^{3} \times {q}^{3}) \times (\frac{1}{ {p}^{2} \times q})[/tex]
• [tex]= \frac{{p}^{5} \times {p}^{3} \times {q}^{3}}{{p}^{2} \times q} [/tex]
• [tex]= \frac{{p}^{5 + 3} \times {q}^{3}}{{p}^{2} \times q} [/tex]
• [tex]= \frac{{p}^{8} \times {q}^{3}}{{p}^{2} \times q} = {p}^{8 - 2} \times {q}^{3 - 1} = {p}^{6} \times {q}^{2} [/tex]

SOAL B.

• [tex]\frac{({ - 4m}^{3} \times {2n}^{5})}{(\frac{8m}{n})} = ({ - 4m}^{3} \times {2n}^{5}) \times (\frac{n}{8m})[/tex]
• [tex]= \frac{{ - 4m}^{3} \times {2n}^{5} \times n}{8m} [/tex]
• [tex]= \frac{{ - 4m}^{3} \times {2n}^{5 + 1}}{8m} [/tex]
• [tex]= \frac{{ - 4m}^{3} \times {2n}^{6}}{8m} [/tex]
• [tex]= \frac{( - 4 \times 2) \times {m}^{3} \times {n}^{6}}{8m} [/tex]
• [tex]= \frac{{ - 8m}^{3} \times {n}^{6}}{8m} [/tex]
• [tex]= ( - 1) {m}^{3 - 1} \times {n}^{6} = { - m}^{2} \times {n}^{6} [/tex]

Answer 2

A

[tex] = {p}^{5} \times (p \times q) {}^{3} ( \frac{1}{ {p}^{2}q } )[/tex]

[tex] = \frac{ {p}^{5} (pq) {}^{3} }{ {p}^{2} q} [/tex]

[tex] = \frac{ {p}^{5} {p}^{3} {q}^{3} }{ {p}^{2} q} [/tex]

[tex] = {p}^{5 + 3 - 2} {q}^{3 - 1} [/tex]

[tex] = {p}^{6} {q}^{2} [/tex]

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B

[tex] = \frac{ - 4 {m}^{3} \times 2 {n}^{5} }{ \frac{8m}{n} } [/tex]

[tex] = \frac{ - \cancel8 {m}^{3} {n}^{5} }{ \cancel8m {n}^{ - 1} } [/tex]

[tex] = - {m}^{3 - 1} {n}^{5 - ( - 1)} [/tex]

[tex] = - {m}^{2} {n}^{6} [/tex]