Question

Sederhanakan 8^log 32 + 4 8^log 4 - 8^log 128

Answer 1

Verified answer

⁸log32 + 4. ⁸log4 - ⁸log128
= ⁸log32 + ⁸log4⁴ - ⁸log128
= ⁸log32 + ⁸log256 - ⁸log128
= ⁸log(32 x 256 : 128)
= ⁸log(32 x 2)
= ⁸log64
= ⁸log8²
= 2 . ⁸log8
= 2

Answer 2

Verified answer

Materi : Logaritma
Kelas : X SMA

⁸log 32  + 4 . ⁸log 4 - ⁸log128
= 5/3 ²log2 + 4 . 2/3 ²log2 - 7/3 ²log2
= 5/3 + 8/3 - 7/3 . 1
= 6/3
= 2