Secepatnya ya!!! lat 1: 3 ya!.... Question from @NobiNobita

DwiArioPrabowo 1) √8 - √20 +2√45 -√72
=√4x2 -√4x5 +2√9x5 -√9x4x2
=2√2- 2√5 +6√5-6√2
=4√5 -4√2
2) 6√72 -6√8 +√20 -3√45
=6√9x4x2 -6√4x2 +√4x5 -3√9x5
=36√2 -12√2 +2√5 -9√5
= -7√5 +24√2
Ijin Sruputt poinnya gan ., Semoga membantu :D

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DwiArioPrabowo Bintang 5 Donk :D

NobiNobita Bantuin aku dong + jujur express the following expressions in their positive integer exponents!

DwiArioPrabowo Ane kurang faham bahasa inggris gan

NobiNobita bukan aku ad soal di dlm nya

NobiNobita 40 point \

ImmanuelSinaga $\text{Bagian A}~: \\ \\ =\sqrt{8}-\sqrt{20}+2\sqrt{45}-\sqrt{72} \\ \\=\sqrt{2^2~\times2}~-~\sqrt{2^2\times5}+2\sqrt{3^2\times5}-\sqrt{2^2\times2\times3^2} \\ \\ =2\sqrt{2}-2\sqrt{5}+(2\times3)\sqrt{5}-(2\times3)\sqrt{2} \\ \\ =2\sqrt{2}-2\sqrt{5}+6\sqrt{5}-6\sqrt{2} \\ \\ =(2-6)\sqrt{2}-(2-6)\sqrt{5} \\ \\ =-4\sqrt{2}~+~4\sqrt{5}$

$\text{Bagian B}~: \\ \\ =6\sqrt{72}-6\sqrt{8}+\sqrt{20}-3\sqrt{45} \\ \\=6\sqrt{2^2\times2\times3^2}~-~6\sqrt{2^2\times2}+\sqrt{2^2\times5}-3\sqrt{3^2\times5} \\ \\ =(6\times2\times3)\sqrt{2}-(6\times2)\sqrt{2}+2\sqrt{5}-(3\times3)\sqrt{5} \\ \\ =36\sqrt{2}-12\sqrt{2}+2\sqrt{5}-9\sqrt{5} \\ \\ =(36-12)\sqrt{2}+(2-9)\sqrt{5} \\ \\ =24\sqrt{2}-7\sqrt{5}$

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ImmanuelSinaga Tandai best lagi dong :D

ImmanuelSinaga Jawaban terbaik maksudnya

NobiNobita tapi bantuin ak lagi

ImmanuelSinaga Aku bisa bantu , tapi yang mana?

NobiNobita cari aj di aku aku

NobiNobita akun aku

NobiNobita lumayan dapat point bantuin aku dong + jujur express the following expressions in their positive integer exponents!

NobiNobita link nya

NobiNobita point 20

NobiNobita lumayan

Given f(x)= find the values of

Jawab ya pliiss + secepat nya aku tungggu + point 40 simplify the following expressions and express it in its positive integer exponent!!!

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