Sebuah transformator dihubungkan dgn PLN pda tegangan 100 V sehingga menyebabakan kuat arus pda kumparan primer sebesar 10 A jika perbandingan jumlah lilitan primer dan sekunder 1:25 makw hitunglah A.tegangan pda kumparan sekunder B.kuat arus pda kumparan sekunder
nennyrahma
Vp = 100v Ip = 10A Np/Ns = 1:25 Vp/Vs = Np/Ns 100/Vs = 1/25 Vs = 2500
Np/Ns = Is/Ip 1/25 = Is/10 10 = 25 Is 0,4 = Is
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mendokusai
A. Vs = Vp Ns / Np Vs = 100 25 / 1 Vs = 2500 Volt ----------------------------------------- B. Is = Vp Ip / Vs Is = 100 10 / 2500 Is = 2/5 Is = 0,4 Ampere
Ip = 10A
Np/Ns = 1:25
Vp/Vs = Np/Ns
100/Vs = 1/25
Vs = 2500
Np/Ns = Is/Ip
1/25 = Is/10
10 = 25 Is
0,4 = Is
Vs = Vp Ns / Np
Vs = 100 25 / 1
Vs = 2500 Volt
-----------------------------------------
B.
Is = Vp Ip / Vs
Is = 100 10 / 2500
Is = 2/5
Is = 0,4 Ampere
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