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Verified answer
Vp = 220 voltVs = 440 volt
Is = 0,2 Ampere
Ip = ?
Vp : Vs = Is : Ip
220 : 440 = 0,2 : Ip
1 : 2 = 0,2 : Ip
Ip = 2 × 0,2
Ip = 0,4 Ampere
jadi kuat arus yang masuk adalah 0,4 Ampere
Vs=440 volt
Is=0,2 Ampere
Ip?
penyelesaian;
Vp/Vs=Is/Ip
220/440=0,2/Ip
Ip×220=440×0,2
Ip=88/220
Ip=0,4 Ampere
jadi kuat arus yang masuk adalah 0,4 Ampere