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Verified answer
Diket :Pp = 720 w
Vs =72 v
Is = 6 A
dit : efisiensi
jwb :
# daya sekunder
Ps = Is . Vs
Ps = 6 . 72
Ps = 432 watt
# efisiensi
ef = (Ps / Pp ) . 100%
ef = ( 432 / 720 ) . 100%
ef = 60 %