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r = 10/2 = 5 cm
t = 12 cm
s² = t² + r² = 5² + 12² = 25 + 144
s² = 169
s = √169 = 13
L selimut kerucut = π r s = 3,14 x 5 x 13 = 204,1 cm² (C)
s² = r² + t²
s² = 5² + 12² ---> s² = 25 + 144 ; s = 13 cm
= 169
Luas selimut = πrs
= 3,14 . 5 . 13
= 204,1 cm²