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D = 42 cm
jrk lmpu = 6 m
maka :
K = 22/7 x d
= 22/7 x 42
= 132 m
Jumlh lmpu y dibutuhkn = 132/6 = 22 lmpu (B)
setiap 6 m diberi lampu
banyak lampu yg diperlukan ?
K = π × d
K = 22/7 × 42
K = 132
132/6 = 22 (B)