Question

Sebuah taman berbentuk persegi panjang dg ukuran panjang (2x+5) m dan lebar (3x-2) m. jika keliling taman 46m maka luas taman=

Answer 1

2x+5+3x-2=46/2
2x+3x=23-5+2
x=20/5
x=4
p=8+5=13cm
l=12-2=10cm
L=p x l=
13 x 10=130cm²

Answer 2

P = 2x + 5
l = 3x - 2
K = 46 m

K = 2p + 2l
46 = 2(2x + 5) + 2(3x - 2)
46 = 4x + 10 + 6x - 4
46 = 10x + 6
10x = 46 - 6
10x = 40
x = 40 : 10
x = 4

p = 2x + 5
p = 2(4) + 5
p = 8 + 5
p = 13 m

l = 3x - 2
l = 3(4) - 2
l = 12 - 2
l = 10 m

Luas = p x l
Luas = 13 x 10
Luas = 130

Jadi, luas taman = 130